SQL LEFT JOIN 关键字
SQL LEFT JOIN 关键字
LEFT JOIN 关键字从左表(table1)返回所有的行,即使右表(table2)中没有匹配。如果右表中没有匹配,则结果为 NULL。
SQL LEFT JOIN 语法
SELECT
column_name(s)
FROM table1
LEFT JOIN table2
ON table1.column_name = table2.column_name ;
FROM table1
LEFT JOIN table2
ON table1.column_name = table2.column_name ;
或:
SELECT
column_name(s)
FROM table1
LEFT OUTER JOIN table2
ON table1.column_name = table2.column_name ;
FROM table1
LEFT OUTER JOIN table2
ON table1.column_name = table2.column_name ;
注释: 在某些数据库中,LEFT JOIN 称为 LEFT OUTER JOIN。
演示数据库
在本教程中,我们将使用 yssmx 样本数据库。
下面是选自 "Websites" 表的数据:
+----+--------------+---------------------------+-------+---------+ | id_name _url _alexa_country | +----+--------------+---------------------------+-------+---------+ | 1 _Google _https://www.google.cm/ _1 _USA | | 2 _淘宝 _https://www.taobao.com/ _13 _CN | | 3 _云搜索MX教程 _/ _4689 _CN | | 4 _微博 _http://weibo.com/ _20 _CN | | 5 _Facebook _https://www.facebook.com/_3 _USA | | 7 _stackoverflow_http://stackoverflow.com/_ 0_IND | +----+---------------+---------------------------+-------+---------+
下面是 "access_log" 网站访问记录表的数据:
mysql> SELECT * FROM access_log; +-----+---------+-------+------------+ | aid_site_id_count_date | +-----+---------+-------+------------+ | 1_ 1_ 45_2016-05-10 | | 2_ 3_ 100_2016-05-13 | | 3_ 1_ 230_2016-05-14 | | 4_ 2_ 10_2016-05-14 | | 5_ 5_ 205_2016-05-14 | | 6_ 4_ 13_2016-05-15 | | 7_ 3_ 220_2016-05-15 | | 8_ 5_ 545_2016-05-16 | | 9_ 3_ 201_2016-05-17 | +-----+---------+-------+------------+ 9 rows in set (0.00 sec)
SQL LEFT JOIN 实例
下面的 SQL 语句将返回所有网站及他们的访问量(如果有的话)。
以下实例中我们把 Websites 作为左表,access_log 作为右表:
实例
SELECT Websites.name, access_log.count, access_log.date
FROM Websites
LEFT JOIN access_log
ON Websites.id=access_log.site_id
ORDER BY access_log.count DESC;
FROM Websites
LEFT JOIN access_log
ON Websites.id=access_log.site_id
ORDER BY access_log.count DESC;
执行以上 SQL 输出结果如下:
注释: LEFT JOIN 关键字从左表(Websites)返回所有的行,即使右表(access_log)中没有匹配。